An argument for mind

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STT said:
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True. But what this has to do with what I said?
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It is possible that X can end and Y begin, simultaneously.

A day changes from one to another at midnight.
 
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STT said:
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Vico:
It is possible that X can end and Y begin, simultaneously.
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That means that the system is in two different state at the same time. This is impossible.
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No, there is no break of time continuity in the position formula – it is contiguous. State X does not exist at time T and State Y exists at time T, one exists and the other does not, simulteneously.
 
I don’t know what your getting at. Have you been to Northern Ireland? The reason I as is I live in NI and what you say sounds like what I read here. One side has to vanish before something else can take place, but nothing when the other side vanishes - like one side can’t exist without the other, two related, both sides can experience how each other thinks because they are related?
 
AlsoRan said:
I don’t know what your getting at. Have you been to Northern Ireland? The reason I as is I live in NI and what you say sounds like what I read here. One side has to vanish before something else can take place, but nothing when the other side vanishes - like one side can’t exist without the other, two related, both sides can experience how each other thinks because they are related?
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You have nothing between. Therefore both side cannot know what other part thinks.
 
Vico said:
No, there is no break of time continuity in the position formula – it is contiguous. State X does not exist at time T and State Y exists at time T, one exists and the other does not, simulteneously.
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Continuous process is not simultaneous. The point ty is after tx.
 
STT said:
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Vico:
No, there is no break of time continuity in the position formula – it is contiguous. State X does not exist at time T and State Y exists at time T, one exists and the other does not, simulteneously.
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Continuous process is not simultaneous. The point ty is after tx.
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You stated: “X and Y cannot exist at the same point therefore X has to vanish before Y takes place.”
X can vanish simultaneously with Y existing – only one exists at a time.
 
Vico said:
You stated: “X and Y cannot exist at the same point therefore X has to vanish before Y takes place.”
X can vanish simultaneously with Y existing – only one exists at a time.
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Does X exist at a point?
 
STT said:
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Vico:
You stated: “X and Y cannot exist at the same point therefore X has to vanish before Y takes place.”
X can vanish simultaneously with Y existing – only one exists at a time.
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Does X exist at a point?
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The state X may exist over many points with the same position, but a minimum of one point. The state X ceases to exist at the time when Y exists.
 
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Vico said:
The state X may exist over many points with the same position, but a minimum of one point. The state X ceases to exist when Y exists.
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What I am arguing is that the point that X exist cannot be the point that X doesn’t exist.
 
STT said:
What I am arguing is that the point that X exist cannot be the point that X doesn’t exist.
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Simultaneous refers to time. The point is position, which is different, so it a different state, at the same time. One state exists and the other state does not at the same time, not position.
 
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Vico said:
Simultaneous refers to time. The point is position, which is different, so it a different state, at the same time. One state exists and the other state does not at the same time, not position.
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I am talking about points on time.
 
Vico said:
Say function p(t) give the position at time t. Then p(t0) could describe state X and p(t1) state Y if the value of p(t0) =/= p(t1). Then it can be said that state X ceases and state Y begins at time t1.
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Yes. That is what I am trying to say.
 
STT said:
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Vico:
Say function p(t) give the position at time t. Then p(t0) could describe state X and p(t1) state Y if the value of p(t0) =/= p(t1). Then it can be said that state X ceases and state Y begins at time t1.
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Yes. That is what I am trying to say.
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Good, then it is possible that state X can end and state Y begin, simultaneously.
 
STT said:
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Vico:
Good, then it is possible that state X can end and state Y begin, simultaneously.
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No. That is impossible. You could have p(t0)=p(t1) which states that there is no change.
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It was given that there is a change: p(t0) =/= p(t1).

At time t0 state X exists and Y does not, simultaneously.
At time t1 state Y exists and X does not, simultaneously.
Code: 
| time | state | exists |
|------|-------|--------|
| t0   | X     | Yes    |
| t0   | Y     | No     |
| t1   | X     | No     |
| t1   | Y     | Yes    |
 
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Vico said:
It was given that there is a change: p(t0) =/= p(t1).

At time t0 state X exists and Y does not, simultaneously.
At time t1 state Y exists and X does not, simultaneously.
Code: 
| time | state | exists |
|------|-------|--------|
| t0   | X     | Yes    |
| t0   | Y     | No     |
| t1   | X     | No     |
| t1   | Y     | Yes    |
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Yes, that is accurate. Now I see what do you mean.
 
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