Question About Hilbert's Hotel

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But its not logically acceptable for there to be equal infinite sets of both 1-10 and set 1 3 5 7 9, AND for there to be equal numbers in both series.
You are talking about “infinite sets” and yet you use finite sets, {1 … 10} and {1 3 5 7 9} as examples. That is an obvious error. You are correct that the two finite sets cannot be put into a one-to-one correspondence; the same does not apply to the infinite sets of natural numbers and odd numbers.

Have you worked out the rule for my character-string example yet? Doing so will help you understand.

rossum
 
It has been explained n times why there is a 1-1 correspondence between {1,2,3,…} and {1,3,5,…}.
He has already agreed to it, though I had to use character strings to help, {nmd, sgqdd, ehud, rdudm, … }.

rossum
 
You are talking about “infinite sets” and yet you use finite sets, {1 … 10} and {1 3 5 7 9} as examples. That is an obvious error. You are correct that the two finite sets cannot be put into a one-to-one correspondence; the same does not apply to the infinite sets of natural numbers and odd numbers.

Have you worked out the rule for my character-string example yet? Doing so will help you understand.

rossum
I admit that your character-string is right and contradicts my argument.

However, my argument was not about a finite number of sets as you just said, but about an infinite number of sets {1-10} and {1 3 5 7 9}, each step having a one to one correspondence, but there forever being 5 more numbers in each set of the first series. So my conclusion must be that infinity just doesn’t make sense and our minds are to limited to make sense of it
 
I admit that your character-string is right and contradicts my argument.

However, my argument was not about a finite number of sets as you just said, but about an infinite number of sets {1-10} and {1 3 5 7 9}, each step having a one to one correspondence, but there forever being 5 more numbers in each set of the first series. So my conclusion must be that infinity just doesn’t make sense and our minds are to limited to make sense of it
thi…
When you start invoking an infinite set of sets you are jumping to the next cardinal number aleph (1) that is infinitely greater than the set of all rational numbers aleph (0). In fact:

aleph(1) = 2^ aleph(0).

You can’t create an infinite set of sets that are countable,
…1…2…3 …
{1-10}, {1,3,5,7,9},. {?} …

What subset comes next??

Yppop
 
The next set would be {11-10}. Why are you now saying that these are uncountable infinities when before you said that they were countable?
 
I admit that your character-string is right and contradicts my argument.
It does, in fact my character string example explicitly contradicts your argument. You have agrees that it does, and so you have lost here. My set of character strings was derived using a simple Caesar shift encryption. Just move each letter in my strings forward one in the alphabet:

nmd → one
sgqdd → three
ehud → five
rdudm → seven
etc.

The character sequence never ends, and given any member of the sequence I can always derive the next member of the sequence.

You have agreed that my character-string set can be put into a one-to-one relationship wit the natural numbers. My character-string set can also, obviously, be put into a one-to-one relationship with the odd numbers. Hence, the set of natural numbers can be put into a one-to-one relationship with the set of odd numbers. QED.

rossum
 
The next set would be {11-10}. Why are you now saying that these are uncountable infinities when before you said that they were countable?
T…
Quit blowing smoke, I never wrote that an infinite set of sets is countable. And just so you know what I am talking about here is the phrase I embolden from your post: “…infinite number of sets {1-10} and {1 3 5 7 9}, each step having a one to one correspondence…”.

If you are not referring the infinity of “power sets”: and the next set is (11-20), what is the next set, (11,13,15,17,19)?

Am I to assume that your sequence would be (1-10), (odds in 1-10), (11-20), (odds in 11-20), (21-30), (odds in 21-30)…to… aleph(0).

Wow. I think you just created and infinity with more odd numbers than integers.

You seem to be adamant about having the last word, a bit of insecurity perhaps? I will yield to you on that score. Take a free shot.
Yppop
 
I just want to learn on these forums.

“I think you just created an infinity with more odd numbers than integers”

How is that possible?

“You can’t create an infinite set of sets that are countable”

Your position over the past two months has been that all the subsets, and there subsets, of all integers are all countable and equal to each other.

Here is the bottom line: if there is a one to one correspondence between all the odd numbers and all the whole natural numbers, then there is a ONE to ONE correspondence, and nothing missing. Therefore if I add one single number to the odd numbers, that set will be greater than the whole natural numbers, because there is NO NUMBER for it to correspond with, since there is already a complete one to one correspondence.

I am pretty sure that the “Caesar shift encryption” is just blurring the regular 1 2 3 4 5 and to infinity set, and not one of its subsets.

Anyway, I’ve recently moved towards a form of Solipsism because of Zeno’s paradox (how can one do an infinity of tasks in motion?) and because of a larger segment lining up with a smaller segment when put on a diagonal (although there is no actual position of points)
 
Here is the bottom line: if there is a one to one correspondence between all the odd numbers and all the whole natural numbers, then there is a ONE to ONE correspondence, and nothing missing.
Correct. Every natural number n corresponds with a single odd number 2n-1.
Therefore if I add one single number to the odd numbers
Above you said “all the odd numbers” so you have no more odd numbers to add. If you add a single non-odd number, say 4, then you no longer have the set of odd numbers, but a different set.

That new set is still in a one-to-one correspondence with the natural numbers. What you can do is to shift every odd number along one, leaving a space at the start for your extra number.

Before we have:

1 → 1
2 → 3
3 → 5
4 → 7

n → 2n-1


With a shift of 1 and inserting 4 at the start, we have:

1 → 4
2 → 1
3 → 3
4 → 5
5 → 7

n → 2n-3


Both sets are still in a one-to-one correspondence. Note that the formula changes, because of the shift of one position, and the formula no longer works for the first entry, since that is the inserted extra even number.
that set will be greater than the whole natural numbers, because there is NO NUMBER for it to correspond with, since there is already a complete one to one correspondence.
That correspondence can be shifted by 1, so leaving a space at the beginning to insert the additional number, 4 in my example.
I am pretty sure that the “Caesar shift encryption” is just blurring the regular 1 2 3 4 5 and to infinity set, and not one of its subsets.
It was an attempt to get you thinking in terms of sets, rather than in terms of numbers. This concept needs to be seen in terms of sets and their elements.

rossum
 
If there is a one to one correspondence between all the odd numbers and all the odd plus even numbers, every position is lined up, every single number is paired. So adding an even number to the odd set would make the odd plus (say) 4 greater than the odd plus all even numbers.

I think this is an area of math were mathematicians are willing to be irrational but some reasons
 
If there is a one to one correspondence between all the odd numbers and all the odd plus even numbers, every position is lined up, every single number is paired. So adding an even number to the odd set would make the odd plus (say) 4 greater than the odd plus all even numbers.

I think this is an area of math were mathematicians are willing to be irrational but some reasons
What? No. You can’t add 4 to the set of all odd numbers. 4 is not an odd number. If you added 4 to the set of all numbers, you would have “the set of all odd numbers, and 4” The set of all odd numbers, and the set of all odd numbers and 4 are completely different sets.
 
If there is a one to one correspondence between all the odd numbers and all the odd plus even numbers, every position is lined up, every single number is paired. So adding an even number to the odd set would make the odd plus (say) 4 greater than the odd plus all even numbers.

I think this is an area of math were mathematicians are willing to be irrational but some reasons
We have repeatedly shown that “all the positive integers” and “all the odd integers” can be lined up in a one-to-one correspondence.

I have also shown that “all the positive integers” and “all the odd integers and 4” can be lined up in a one-to-one correspondence. All I did was to shift the odd integers along by one step; instead of 1 → 1, I used 2 → 1. That left things clear for 1 → 4 to accommodate the extra 4 in the set “all the odd integers and 4”. It was the equivalent of the manager of Hilbert’s Hotel moving every guest to the next room along, so freeing up one room for a newly arrived guest, the “4”.

rossum
 
Where have you proven that?

By shifting the numbers around as you have you have admitted there is no one to one correspondence. If every odd number lines up with every odd number AND every even number (uhhh?), then any ANY one number to the odd series would make that series greater. THAT is an argument, and we can’t progress in understanding on this thread until you admit this.

By how much is an uncountable infinity greater then a countable infinity? Whatever that number is, does it matter if it is greater than one? No. So one number added to the odd numbers make it a greater series then it was.

Therefore the odd plus even numbers are greater than the odd numbers.

Anything contrary to this clear common sense takes all the rationality out of arithmetic.
 
By shifting the numbers around as you have you have admitted there is no one to one correspondence.
No, I have shown that there are two different one-to-one correspondences between two different pairs of sets. The first correspondence is between the positive integers and the odd integers. The second correspondence is between the positive integers and the odd integers with four. The second set in the correspondences are different, so the correspondences are also different.

A different pair of sets results in a different correspondence.
By how much is an uncountable infinity greater then a countable infinity?
An interesting question, and one I am not qualified to answer. I suspect that the difference is itself an uncountable infinity, but I am ready to be proved wrong.
So one number added to the odd numbers make it a greater series then it was.
But the new set is still a countable infinity. There is more than one set with a countable infinity of elements. For example, the set of all possible words is a countable infinity.
Therefore the odd plus even numbers are greater than the odd numbers.
Not in terms of the set algebra we are discussing here. C{odd + even} = C{odd} is the correct answer, where C{…} is the Cardinal Number of the set. As I said, this problem involves set algebra.

rossum
 
I don’t see how there can be two different one-to-one correspondences IF one to one correspondence means there are only pairs between the two sets. If that is the definition, the addition of even one number to one or the other set would make it larger.

Anyway, my thing with the 2n-1 function is that I don’t believe it has any **operational **power.
 
I don’t see how there can be two different one-to-one correspondences IF one to one correspondence means there are only pairs between the two sets…
Here is an example of two different 1-1 correspondences between the sets A and B.
A={1,2,3}
B={a,b,c}
Correspondence number 1:
1-a
2-b
3-c
Correspondence number 2
1-c
2-a
3-b
 
I don’t see how there can be two different one-to-one correspondences
They have to be different. The first correspondence is between set A and set B. The second correspondence is between set A and set C, where set B is not the same as set C. Since there are different sets involved, then the correspondences are also different.
IF one to one correspondence means there are only pairs between the two sets. If that is the definition, the addition of even one number to one or the other set would make it larger.
Your logic assumes finite sets, not infinite sets. Since we are dealing with countably infinite sets here, then you logic does not apply.

rossum
 
Tomdstone, changing a series from 1 2 3 to 3 1 2 doesn’t address what we are talking about here.

Furthermore, a one to one correspondence means by definition that they all line up with each other TO INFINITY. The infinity doesn’t change the fact that that forever they are lined up. I think there is something convoluted and jumpy about your conception of infinity. But I feel that my thought on it, as if it was a series going towards the horizon with an infinity of pairs, is the honest and true one.

But so many mathematicians in this present era believe what I don’t!?

Welcome to the real world (its strangely imperfect)
 
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