When v<<rw then eq 5n is left with 1/2mr^2w^2
When v>>rw then eq 5n is left with 1/2m*v^2
That’s why I said the kinetic energy is almost constant in the ground frame as well.
As I said before, I’m not sure this is the right forum for this discussion. As far as I can tell, no-one is reading this other than you and me, which, in effect, means that I’m giving you a personal physics tutorial. I’ll answer these most recent questions of yours, but I can’t continue to teach you physics via this forum.
As I said, as v increases so does the amplitude of the kinetic energy cycle The amplitude of the cycle for a given r
omega increases as a linear function of v. The bigger v, the bigger the amplitude of the kinetic energy cycle. However if you consider the amplitude of the kinetic energy cycle as a fraction of the mean kinetic energy it looks like this for romega=1:
rolling | Alec Mac&roo | Flickrfarm9.staticflickr.com/8601/16048514099_f3450f706a_n.jpg
where the x-axis is v and the y-axis is (amplitude of kinetic energy cycle)/(mean kinetic energy). As you can see this ratio is maximum for v=r*omega but this is **not **a resonance because this system does not have a harmonic oscillator.
Let us assume m=1, v=1, r=1, w=1, all equal 1
When v ~ rw (actually v=rw in this case) then eq 5n gives us:
at 0 the kinetic energy is 1/2(1 + 1 - 2) = 0
at pi the kinetic energy is 1/2(1 + 1 + 2) = 2
… and back to 0 at 2pi and back to 2 at 3pi, …
How does it happen? Do you still think there is no oscillation?
How many times do I have to repeat the same thing? The kinetic energy cycles because work is being done on the body in what you call the ground frame by the force of the string which is an external force. This force, acting in the direction of the string is not always perpendicular to the velocity of the body in this frame and so work is done which is the source of the varying energy. There are no other forces or accelerations other than in the direction of the string. (In the frame moving with the centre of revolution, the acceleration and velocity are always perpendicular, no work is done and so the kinetic energy remains constant).
Again, how many times do I have to repeat this - there is no natural frequency because there is no oscillator. An oscillator requires a restoring force which is a monotonic function of diplacement (like the force of gravity on a pendulum, or the tension in a spring). Another way of looking at it is that an oscillator requires energy to be exchanged between two forms of energy - in a mechanical oscillator between kinetic and potential energy for example which is also not occurring here.
So when the train moves at a constant velocity what external forces are being applied?
Applied to what? We don’t have a real train here - we just have something to visualise an inertial frame of reference. Unless you want to include an actual train in the kinematic system to which the other end of the string is attached. We can do that analysis if you want but it’s not the analysis represented by your maths. In that case you have to include the train in the energy calculations and you’ll have a kinematically complete system in which the kinetic energy is constant in all inertial frames (whatever energy is gained or lost by the revolving body is lost or gained by the train so that the total energy of the system remains constant - in all inertial frames.)
But at the moment the problem is set up so we are considering a massless infinitely stiff string being the means for revolving the body. You haven’t specified what is on the other end of the string (but you specify that it moves in an inertial frame). So the force provided by the string is an external force to the system under consideration and therefore the energy of the body as an isolated kinematically incomplete system can be constant in some inertial frames and vary in others.
There are no external force acting on the ground reference frame and there are no external forces acting on the train because it has a constant velocity.
If you are attaching the revolving mass to an actual train with a finite mass (as actual trains possess) then the train
cannot be at rest in an inertial frame because the reactive force of the body revolving will cause the train’s velocity to vary in an inertial frame (in such a way that the total energy of the entire system - revolving body plus train - is constant in all inertial systems. So to summarise - if you include the train as a kinematic element of a complete system, there are no external forces and the energy of the complete system is constant in all inertial frames. If you consider the body only (as you have been doing in the maths etc) then this is not a kinematically complete system and the string is applying an external force to the system of the body. In this case, as we have seen, the kinetic energy of the revolving body on its own is constant in some inertial frames and not in others.
From the beginning I specified two inertial reference frame systems so it’s clear the scenario is in line with the fact that the Galilean invariance does demand the kinetic energy to be constant.
It doesn’t if there is an external force applied as in the scenario as described.
I recommend that you read my reply very carefully and think very hard about it. Try to forget you preconceptions (they are wrong) and don’t focus on arguments to prove me wong (I’m correct - I do this stuff as a profession). If you can think about this very carefully, accepting that you don’t understand the physics (you don’t, you really don’t), then it’s possible that you’ll learn some physics. Otherwise you are doomed to keep repeating the same elementary mistakes.